-10a^2+4a+1=0

Solution for -10a^2+4a+1=0 equation:

-10a^2+4a+1=0

a = -10; b = 4; c = +1;
Δ = b2-4ac
Δ = 42-4·(-10)·1
Δ = 56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{56}=\sqrt{4*14}=\sqrt{4}*\sqrt{14}=2\sqrt{14}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{14}}{2*-10}=\frac{-4-2\sqrt{14}}{-20}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{14}}{2*-10}=\frac{-4+2\sqrt{14}}{-20}
$